V tom odkazu pisi neco jineho:
If one drive fails in a RAID 5E/5EE array then the array is 'compressed' and re-built (re-striped) into a standard RAID 5 array. This process can be very intensive on the drive I/O if the array is made up of less than 10-disks and the process may take several hours depending on the speed of the drives. Once the failed drive is replaced, the array is this time 'decompressed' and re-built (re-stripped) back into a RAID 5E/5EE array. The process may take several hours depending on the speed of the drives. The process can also be very intensive on the drive I/O if the array is made up of less than 10 disks. During the 'compressing' and 'decompressing' stages the array is at risk of a second disk failure as the array is not protected by redundancy during those stages.
Prechod z 5EE na 5 neni ihned a behem toho prechodu neni pole redudantni. Pokud to je pravda, tak bych radeji volil sice pomalejsi, ale spolehlivejsi RAID 6. Kazdopadne tedy beres zpet tvrzeni, ze 5EE potrebuje stejne disku jako 5?
Jinak to co IBM nazyva 1E se v linuxu nazyva 10, ktery navic vyborne skaluje pri velkem I/O zatizeni. Je to v tom odkazu take.